Why did Rutherford select a gold foil in his alpha–ray scattering experiment?
Rutherford used gold for his scattering experiment because gold is the most malleable metal and he wanted the thinnest layer as possible.
Therefore, Rutherford selected a Gold foil in his alpha scattering experiment.
In response to a question, a student stated that in an atom, the number of protons is greater than the number of neutrons, which in turn is greater than the number of electrons. Do you agree with the statement? Justify your answer.
The statement is wrong because the number of protons can never be greater than the number of neutrons. The number of protons will always be less than or equal to the number of neutrons. The number of electrons and protons are always equal in a neutral atom.
Will 35Cl and 37Cl have different valencies? Justify your answer.
35Cl and 37Cl cannot have different valencies because they are the isotopes of the same element.
Write any two observations which support the fact that atoms are divisible
Is it possible for the atom of an element to have one electron, one proton and no neutron. If so, name the element.
Yes, Hydrogen is the element which is having only 1 proton and 1 electron and no neutron hence there is no repulsive force in the nucleus hence it is stable.
Calculate the number of aluminium ions present in 0.051g of aluminium oxide.
(Hint: The mass of an ion is the same as that of an atom of the same element. Atomic mass of Al = 27u)
To calculate the number of aluminium ions in 0.051g of aluminium oxide:
1 mole of aluminium oxide = 6.022 x 1023 molecules of aluminium oxide
1 mole of aluminium oxide (Al2O3) = 2 x Mass of aluminium + 3 x Mass of Oxygen
= (2x 27) + (3 x16) = 54 +48 = 102g
1 mole of aluminium oxide = 102g = 6.022 x 1023 molecules of aluminium oxide
Therefore, 0.051g of aluminium oxide has = 0.051 x 6.022 x 1023 / 102
= 3.011 x 1020 molecules of aluminium oxide
One molecule of aluminium oxide has 2 aluminium ions, hence number of aluminium ions present in 0.051g of aluminium oxide = 2 x 3.011x 1020 molecules of aluminium oxide
= 6.022 x 1020
Calculate the number of molecules of sulphur (S8) present in 16g of solid sulphur.
To calculate molecular mass of sulphur:
Molecular mass of Sulphur (S8) = 8xMass of Sulphur = 8×32 = 256g
Mass given = 16g
Number of moles = mass given/ molar mass of sulphur
= 16/256 = 0.0625 moles
To calculate the number of molecules of sulphur in 16g of solid sulphur:
Number of molecules = Number of moles x Avogadro number
= 0.0625 x 6.022 x 10²³ molecules
= 3.763 x 1022 molecules
What is the mass of:
(a) 0.2 mole of oxygen atoms?
(b) 0.5 mole of water molecules?
The mass is as follows:
(a) Mass of 1 mole of oxygen atoms = 16u, hence it weighs 16g
Mass of 0.2 moles of oxygen atoms = 0.2 x 16 = 3.2u
(b) Mass of 1 mole of water molecules = 18u, hence it weighs 18g
Mass of 0.5 moles of water molecules = 0.5 x 18 = 9u
Convert into mole.
(a) 12g of oxygen gas
(b) 20g of water
(c) 22g of carbon dioxide
Conversion of the above-mentioned molecules into moles is as follows:
(a) Given: Mass of oxygen gas=12g
Molar mass of oxygen gas = 2 Mass of Oxygen = 2 x 16 = 32g
Number of moles = Mass given / molar mass of oxygen gas = 12/32 = 0.375 moles
(b) Given: Mass of water = 20g
Molar mass of water = 2 x Mass of Hydrogen + Mass of Oxygen = 2 x 1 + 16 = 18g
Number of moles = Mass given / molar mass of water
= 20/18 = 1.11 moles
(c) Given: Mass of carbon dioxide = 22g
Molar mass of carbon dioxide = Mass of C + 2 x Mass of Oxygen = 12 + 2x 16 = 12+32=44g
Number of moles = Mass given/ molar mass of carbon dioxide = 22/44 = 0.5 moles
What is the mass of –
(a) 1 mole of nitrogen atoms?
(b) 4 moles of aluminium atoms((Atomic mass of aluminium =27)?
(c) 10 moles of sodium sulphite (Na2SO3)?
The mass of the above mentioned list is as follows:
(a) Atomic mass of nitrogen atoms = 14u
Mass of 1 mole of nitrogen atoms= Atomic mass of nitrogen atoms
Therefore, mass of 1 mole of nitrogen atom is 14g
(b) Atomic mass of aluminium =27u
Mass of 1 mole of aluminium atoms = 27g
1 mole of aluminium atoms = 27g, 4 moles of aluminium atoms = 4 x 27 = 108g
(c) Mass of 1 mole of sodium sulphite Na2SO3 = Molecular mass of sodium sulphite = 2 x Mass of Na + Mass of S + 3 x Mass of O = (2 x 23) + 32 +(3x 16) = 46+32+48 = 126g
Therefore, mass of 10 moles of Na2SO3 = 10 x 126 = 1260g